Math, asked by eedvranares56, 1 month ago

cos 6x =32 cos ^6X - 48 cos ^ 4 x +18 cos ^2x-1​

Answers

Answered by lalit44702
0

Answer:

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Answered by VidishaRaj
20

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using,

соs2x=2соs

2

x−1

соs3x=4соs

3

x−3соsx

LHS:

соs6x=2соs

2

3x−1

=2(4соs

3

x−3соsx)

2

−1

=2(16соs

6

x+9соs

2

x−24соs

4

x)−1

=32соs

6

x−48соs

4

x+18соs

2

x−1 = RHS

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