Question

Cos(90-A)sin(90-A)/tan(90-A) =sin^2A

Answer 1

We know, cos(90° - θ) = sinθ , sin(90° - θ) = cosθ

and tan(90° - θ) = cotθ .

now from above concepts

cos(90° - A) = sinA ------(1)

sin(90° - A) = cosA ------(2)

tan(90° - A) = cotA ------(3)

LHS = cos(90 - A).sin(90 - A)/tan(90 - A)

= sinA.cosA/cotA [ from (1), (2) and (3)]

= sinA.cosA/(cosA/sinA)

= sin²A = RHS

Answer 2

Answer:

it can be solved by allied angles formulae

Step-by-step explanation:

cos(90-A)=sinA

sin(90-A)=cosA

tan(90-A)=tanA

sinA.cosA.tanA

sinA.cosA.sinA/cosA

sin^2A