Question

Cos(90-A)sin(90-A)/tan(90-A)=sin2A

Answer 1

cos(90-a) sin (90-a)/tan(90-a)
sinA cosA/cot A
sinAcosA/cosA/sinA/2sinA

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Answer 2

Answer:

Step-by-step explanation:

LHS= Cos(90-A).Sin(90-

A)/TAN(90-A)

=SinA.CosA/CotA

=SinA. CosA. SinA/CosA

[because CotA=

CosA/SinA]

=Sin2A

RHS =Sin2A

LHS=RHS

Hence Cos(90-A)sin(90-A)/tan(90-A)=sin2A