The radius of base of two circular cone are equal but the volumeare 4 and 9 find the ratio of the height
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Answered by
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Ans :- 4:9
let the radius of circular cone be r and height of 1 cone be h1 and another be h2
acording to the question
![((1 \div 3)\pi {r}^{2} h1) \div ((1 \div 3)\pi {r}^{2} h2) = 4 \div 9 ((1 \div 3)\pi {r}^{2} h1) \div ((1 \div 3)\pi {r}^{2} h2) = 4 \div 9](https://tex.z-dn.net/?f=%28%281+%5Cdiv+3%29%5Cpi+%7Br%7D%5E%7B2%7D+h1%29+%5Cdiv+%28%281+%5Cdiv+3%29%5Cpi+%7Br%7D%5E%7B2%7D+h2%29+%3D+4+%5Cdiv+9)
after solving we get
h1/h2 = 4/9
let the radius of circular cone be r and height of 1 cone be h1 and another be h2
acording to the question
after solving we get
h1/h2 = 4/9
Answered by
0
Hi...dear...
here is your answer..
4:9 ...let's see how come ...
let the radius of first cone be r1 height h1 and volume V1...
similarly for other one are r2, h2, V2 .. res......pectively...
given that r1= r2...
see picture.....for further solution...
Hope you understand!!
Regards Brainly Star Community
#shubhendu
here is your answer..
4:9 ...let's see how come ...
let the radius of first cone be r1 height h1 and volume V1...
similarly for other one are r2, h2, V2 .. res......pectively...
given that r1= r2...
see picture.....for further solution...
Hope you understand!!
Regards Brainly Star Community
#shubhendu
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