Question

cos(90° - A). sec(180° - A). sin(180° - A)
sin (90° + A). tan(90° + A). cosec (90° + A)​

Answer 1

Step-by-step explanation:

cos(90° - A). sec(180° - A). sin(180° - A)

sin (90° + A). tan(90° + A). cosec (90° + A)

cos(90° - A) = sinA

sec(180° - A)= (- secA)

sin(180° - A) = sinA

sin (90° + A) =cosA

tan(90° + A) = (- cotA)

cosec (90° + A) = secA

The question was not clear... didn't understand whether it is completely one problem or two problems

so all trigonometric ratio r simplified individually...further simplification u can try...

Answer 2

Answer is given in the pic.