Question

cos a/1+sina+1+sina/cosa=2seca

Answer 1

Answer:

Given,. cosA1+sinA+1+sinA cosA. =(cosA⋅cosA)+(1+sinA)(1+sinA)cosA(1 +sinA). =cos2A+1+2sinA+sin2AcosA(1+sinA).

Given, cosA1+sinA+1+sinAcosA =(cosA⋅cosA)+(1+sinA)(1+sinA)cosA(1+sinA) =cos2A+1+2sinA+sin2AcosA(1+sinA) =2+2sinAcosA(1+sinA) (as, cos2A+sin2A=1) ... More

Answer 2

$\frac{cosa}{1 + sina} + \frac{1 + sina}{cosa} \\ \\ = \frac{ {cos}^{2}a + ( {1 + sina})^{2} }{(1 + sina)cosa} \\ \\ = \frac{ {cos}^{2}a + 1 + {sin}^{2} a + 2sina }{(1 + sina)cosa} \\ \\ = \frac{2 + 2sina}{(1 + sina)cosa} \\ \\ = \frac{2}{cosa} \\ \\ = 2seca$