cos A = 2/3 and A+B= 90° find sin B
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cos A= 2/3
A+B =90°
B=90°-A
sin B =90°-A
sin B = cos A
sin B =2/3
A+B =90°
B=90°-A
sin B =90°-A
sin B = cos A
sin B =2/3
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Answered by
3
cos A= 2/3
A+B=90*
B=90*-A
sin B = 90-A
sin B = cos
sin B = 2/3
A+B=90*
B=90*-A
sin B = 90-A
sin B = cos
sin B = 2/3
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