Question

cos A = 2/3 and A+B= 90° find sin B

Answer 1

cos A= 2/3
A+B =90°
B=90°-A

sin B =90°-A
sin B = cos A
sin B =2/3

Answer 2

cos A= 2/3
A+B=90*
B=90*-A
sin B = 90-A
sin B = cos
sin B = 2/3