Question

$
Cos (A-A) cot (1 + A) cos (-A)
Z COSA
tan Cata) tan ish &A) sin 125-A)​

Answer 1

Answer:

tan

2

2

α

cot

−1

(

cosα

)−tan

−1

(

cosα

)=x

2

π

−tan

−1

(

cosα

)−tan

−1

(

cosα

)=x (because cot

−1

x+tan

−1

x=

2

π

)

⇒

2

π

−2tan

−1

(

cosα

)=x

⇒sinx=sin(

2

π

−2tan

−1

(

cosα

))

Let's say tan

−1

(

cosα

)=θ

⇒tanθ=

cosα

sinx=sin(

2

π

−2θ)=cos2θ

=

1+tan

2

θ

1−tan

2

θ

=

1+cosα

1−cosα

sinx=

1+cosα

1−cosα

=

2cos

2

α/2

2sin

2

α/2

⇒sinx=tan

2

2

α

.

Step-by-step explanation:

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