Question

cos(A+B)=0,sin (A-B)=1/2find the value of A andB.

Answer 1

cos(A+B) = 0
=> A+B = 90° ------(i)

sin(A-B) = 1/2
=> A-B = 30° -------(ii)

from (i) and (ii),
A= 60°
B= 30°

Answer 2

SOLUTION...

cos (A+B) = 0
cos (A+B) = cos 90
so, A+B = 90.................... eq (1.)

sin (A-B) = 1/2
sin (A-B) = sin30
so, A-B = 30.................... eq (2.)

On adding eq.1 and eq.2
we get,
A= 60°

now put value of A in eq.1
we get,
B= 30°

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