cos(A+B)=1/2=SIN(A-B)
Answers
Answered by
0
cos(A+B)=1/2
cos(A+B)=cos 60 deg since cos 60 deg=1/2
cancelling cos on both side we get
A+B=60 deg.................................(1)
similarly,
sin(A-B)=1/2
sin(A-B)=sin 30 deg
A-B=30 deg....................................(...
from 1 and 2
A+B+A-B=90 deg
2A=90 deg
A=45 deg
thus B= 15 deg
answers A=45 AND B=15
cos(A+B)=cos 60 deg since cos 60 deg=1/2
cancelling cos on both side we get
A+B=60 deg.................................(1)
similarly,
sin(A-B)=1/2
sin(A-B)=sin 30 deg
A-B=30 deg....................................(...
from 1 and 2
A+B+A-B=90 deg
2A=90 deg
A=45 deg
thus B= 15 deg
answers A=45 AND B=15
sid81686:
hii
hello
are u real in dp
yes
u look so sexy
are u there
no there
Answered by
1
2 answers · Mathematics
Best Answer
cos(A+B)=1/2
cos(A+B)=cos 60 deg since cos 60 deg=1/2
cancelling cos on both side we get
A+B=60 deg.................................(1)
similarly,
sin(A-B)=1/2
sin(A-B)=sin 30 deg
A-B=30 deg....................................(...
from 1 and 2
A+B+A-B=90 deg
2A=90 deg
A=45 deg
thus B= 15 deg
answers A=45 AND B=15
keep smiling :)
Best Answer
cos(A+B)=1/2
cos(A+B)=cos 60 deg since cos 60 deg=1/2
cancelling cos on both side we get
A+B=60 deg.................................(1)
similarly,
sin(A-B)=1/2
sin(A-B)=sin 30 deg
A-B=30 deg....................................(...
from 1 and 2
A+B+A-B=90 deg
2A=90 deg
A=45 deg
thus B= 15 deg
answers A=45 AND B=15
keep smiling :)
Similar questions