Question

cos(A-B) /cosA.sinB = cotB+tanA prove that​

Answer 1

Answer:

$5 {4 \frac{ \frac{22}{?} }{?} }^{2}$

Answer 2

Step-by-step explanation:

cos (A-B)= CosA CosB+ SinA SinB

LHS= cos(A-B)/Cos A Sin B= (CosA CosB+ Sin A Sin B)/Cos A Sin B

= (CosA Cos B/ Cos A Sin B ) + (Sin A Sin B/ Cos A SinB)

= cosB/ sinB + Sin A / Cos A

= CotB + tan A= RHS

Hence proved