Question

help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!​

Answer 1

Answer:

$\frac{\sqrt{3}x^2}{y}$

Step-by-step explanation:

$\frac{3x^3y}{\sqrt{3} xy^2} \\=( \frac{3}{\sqrt{3}} )* x^{3-1} * \frac{1}{y^{2-1}} \\= \frac{\sqrt{3}}{1} * x^2 * \frac{1}{y^1} \\= \frac{\sqrt{3}x^2}{y}$