cos(A-B)=what is the answer
Answers
Answer:
sin(A+B)= sinAcosB+cosAsinB (Remember)
Then, you can easily find sin(A-B).
sin(A-B)= sin(A+(-B))= sinAcos(-B)+cosAsin(-B)=sinAcosB+cosA(-sinB) {since;
cos(-X)=cosX
sin(-X)=sin(X)}
sin(A-B)=sinAcosB-cosAsinB
cos(A+B)=cosAcosB-sinAsinB (Remember)
cos(A-B)=cos(A+(-B))=cosAcos(-B)-sinAsin(-B)=cosAcosB-sinA(-sinB)
cos(A-B)=cosAcosB+sinAsinB
Step-by-step explanation:
sin(A+B)= sinAcosB+cosAsinB (Remember)
Then, you can easily find sin(A-B).
sin(A-B)= sin(A+(-B))= sinAcos(-B)+cosAsin(-B)=sinAcosB+cosA(-sinB) {since;
cos(-X)=cosX
sin(-X)=sin(X)}
sin(A-B)=sinAcosB-cosAsinB
cos(A+B)=cosAcosB-sinAsinB (Remember)
cos(A-B)=cos(A+(-B))=cosAcos(-B)-sinAsin(-B)=cosAcosB-sinA(-sinB)
cos(A-B)=cosAcosB+sinAsinB
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