(Cos A by 1 + sin a) +( 1 + sin a by Cos A )is equal to 2 sec a prove that a lhs is equals to RHS
Answers
Answered by
0
Solution :
RHS =
cosA/( 1 + sinA ) + ( 1 + sinA )/cosA
= [ cos²A + ( 1 + sinA )² ]/[( 1 +sinA )cosA]
= [ cos²A+1+2sinA+sin²A]/[(1+sinA)cosA]
= [(cos²A+sin²A)+1+2sinA]/[(1+sinA)cosA]
= ( 1 + 1 + 2sinA )/[(1+sinA)cosA]
= [2( 1 + sinA )]/[(1+sinA)cosA]
= 2/cosA
= 2secA
= RHS
•••••
RHS =
cosA/( 1 + sinA ) + ( 1 + sinA )/cosA
= [ cos²A + ( 1 + sinA )² ]/[( 1 +sinA )cosA]
= [ cos²A+1+2sinA+sin²A]/[(1+sinA)cosA]
= [(cos²A+sin²A)+1+2sinA]/[(1+sinA)cosA]
= ( 1 + 1 + 2sinA )/[(1+sinA)cosA]
= [2( 1 + sinA )]/[(1+sinA)cosA]
= 2/cosA
= 2secA
= RHS
•••••
Similar questions