Question

Cos a+sin a=p, sec a+cos a=q prove that q( p×p-1 )= 2p

Answer 1

Answer:

Step-by-step explanation:

P= sina + cosa

=> p^2 = (sina +cosa)^2= sin^2 a + cos^2 a + 2sinacosa = 1+ 2sinacosa now p^2-1= 2sinacosa now q(p^2-1) = (seca + cosa)2sinacosa = [1/cosa + 1/sina ] 2sinacosa = (sina + cosa)2 =2(sina+ cosa) = 2 p = RHS proved