cos (cos' (- 1/7) + sin- (- 1/7))
is equal to:
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0
Answer:
We take,
X
=
cos
[
cos
−
1
(
−
1
7
)
+
sin
−
1
(
−
1
7
)
]
We know that,
cos
−
1
x
+
sin
−
1
x
=
π
2
∴
cos
−
1
(
−
1
7
)
+
sin
−
1
(
−
1
7
)
=
π
2
So,
X
=
cos
[
cos
−
1
(
−
1
7
)
+
sin
−
1
(
−
1
7
)
]
⇒
X
=
cos
(
π
2
)
=
0
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