Question

cos ec square 60°+sec square 30°+cos square 45°=​

Answer 1

Step-by-step explanation:

Hey mate,

Here is ur answer,.,.,

We know the trigonometric values,

$\begin{lgathered}\csc 45^\circ=\sqrt{2}\\\\\sec 30^\circ=\frac{2}{\sqrt{3}}\\\\\sin30^\circ= \frac{1}{2}\\\\\cot 45^\circ=1\\\\\sec 60^\circ=2\\\\\end{lgathered}$

=$(2)(\frac{4}{3})(\frac{1}{4})+4-4=(2)$

=$\frac{2}{3}$

Therefore,$\csc^2 45^\circ \sec^2 30^\circ \sin^230^\circ+4\cot^2 45^\circ-\sec^2 60^\circ=\frac{2}{3}$

#Learn more

Evaluate the following sin 30 degrees + tan 45 degrees minus cos tan 60 degrees by cos 45 degrees + Cos 60 degrees minus secant 30 degrees

https://brainly.in/question/11495152

Answer 2

Answer:

cosec^2 60= 2/$\sqrt{3}$ x 2/$\sqrt{3}$= 4/3

sec^2 30= 2/$\sqrt{3}$ x 2/$\sqrt{3}$= 4/3

cos^2 45= 1/$\sqrt{2}$ x 1/$\sqrt{2}$= 1/2

$\frac{4}{3}$ + $\frac{4}{3}$ + $\frac{1}{2}$ = $\frac{8+8+3}{6}$ (LCM of 2 and 3 = 6)

            = 19/6