Question

cos ki power sin x ka avkalan kijiye​

Answer 1

Answer:

let cosx^sinx=y

taking log both side

logcosx^sinx=log y

sinxlogcosx= logy

sinx×1/cosx×-sinx+logcosx×cosx= 1/y dy/Dx

(- sin²x/cosx+ cosxlogxcosx)cosx^sinx=dy/dx