cos (n+2)x cos (n+1)x + sin (n+1)x sin (n+2)x = cos x
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HELLO DEAR,
cos(n+1)xcos(n+2)x + sin(n+1)xsin(n+2)x
it is from the identity
cos(a-b) = cosa * cosb + sina * sinb
here a= (n+1)x b= (n+2)x
so,
cos((n+1)x-(n+2)x)
cos(nx+x-nx-2x)
cos(-x)
cosx { since cos(-x) = cosx }
I HOPE ITS HELP YOU DEAR,
THANKS
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