Question

COS
Q28. Prove that sin theta/ sin (90-theta) + cos / cos(90-theta) =secthetacosectheta

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Answer 1

Answer:

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Answer 2

Answer:

proved

Step-by-step explanation:

=sinθ/sin(90-θ)+cosθ/cos(90-θ)

=sinθ/cosθ+cosθ/sinθ

lcm of cosθ and sinθ

=sin^2+cos^2/sinθcosθ

sin^2+cos^2=1

=  1/sinθcosθ

=1/sinθ*1/cosθ

1/sinθ=cosecθ and 1/cosθ=sec

=secθcosecθ