Cos +sin=1,pt cos-sin=+/-1
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cos(sin−1x) Let, sin−1x=θ ⇒ sinθ=x ⇒sin2θ=x2 ⇒1−cos2θ=x2 ⇒cos2θ=1 −x2 ⇒cosθ=±√1−x2 ⇒θ=cos−1±√1−x2
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Hence proved
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