Question

cos[(sin^-1x+cos^-1x)]=​

Answer 1

Answer:

=cos(sin^-1x+cos^-1x)

=cos(π/2)

= 0

Answer 2

Answer:

0

Step-by-step explanation:

use identity

${ \sin(x) }^{ - 1} + { \cos(x) }^{ - 1} = \pi \div 2$

=Cos(π/2)

=0