cos sqare theta + sin square theta=1. prove that
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in triangle ABC..... let AC be hypotenuse BC be base and AB be perpendicular
use Pythagoras Theo
step 1. (h)²= (p)²+(b)²
step 2. divide (h)² on both sides
step3. (h)²/(h)²= (p)²/(h)²+(b)²/(h)²
step 4. 1 = sin² theta+ cos² theta bcz.. p/h = sin theta
bcz...b/h = cos theta
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