Math, asked by kaushaljare2412, 5 months ago

cos theta/1+sin theta​

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Answered by PharohX
2

Answer:

 \frac{ \cos( \theta) }{1 +  \sin( \theta) }  \\  \\  =  \frac{ \sin( \frac{\pi}{2} -  \theta ) }{1 +  \cos( \frac{\pi}{2} -  \theta ) }  \\  \\   = \frac{2 \sin( \frac{\pi}{4}  -  \frac{\theta}{2} ) . \cos( \frac{\pi}{4}  -  \frac{\theta}{2} )   }{2 \cos ^{2} ( \frac{\pi}{4}  -  \frac{\theta}{2} ) }  \\  \\  =  \frac{\sin( \frac{\pi}{4}  -  \frac{\theta}{2} )}{\cos( \frac{\pi}{4}  -  \frac{\theta}{2} )}  \\  \\  =  \tan( \frac{\pi}{4}  -  \frac{\theta}{2} )

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