cos theta/1-sin theta+cos theta/1+sin theta=4
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Answered by
0
Okay. We've got:
cos
θ
1
−
sin
θ
+
cos
θ
1
+
sin
θ
=
4
Let's ignore the
R
H
S
for now.
cos
θ
1
−
sin
θ
+
cos
θ
1
+
sin
θ
cos
θ
(
1
+
sin
θ
)
+
cos
θ
(
1
−
sin
θ
)
(
1
−
sin
θ
)
(
1
+
sin
θ
)
cos
θ
(
(
1
−
sin
θ
)
+
(
1
+
sin
θ
)
)
1
−
sin
2
θ
cos
θ
(
1
−
sin
θ
+
1
+
sin
θ
)
1
−
sin
2
θ
2
cos
θ
1
−
sin
2
θ
According to the Pythagorean Identity,
sin
2
θ
+
cos
2
θ
=
1
. So:
cos
2
θ
=
1
−
sin
2
θ
Now that we know that, we can write:
2
cos
θ
cos
2
θ
2
cos
θ
=
4
cos
θ
2
=
1
4
cos
θ
=
1
2
θ
=
cos
−
1
(
1
2
)
Answered by
0
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