Question

Cos theta/1 - tan theta + sin theta /1 - cos theta = cos theta + sin theta

Answer 1

cos(θ)1−tan(θ)+sin(θ)1−1tan(θ)=cos(θ)1−(sin(θ)cos(θ))+sin(θ)1−(cos(θ)sin(θ))=cos2(θ)cos(θ)−sin(θ)+sin2(θ)sin(θ)−cos(θ)=cos2(θ)cos(θ)−sin(θ)−sin2(θ)cos(θ)−sin(θ)=cos2(θ)−sin2(θ)(cos(θ)−sin(θ))=(cos(θ)+sin(θ))(cos(θ)−sin(θ))(cos(θ)−sin(θ))=sin(θ)+cos(θ)