Cos theta = 7/8 then evaluate 1+sin theta / cos theta
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Step-by-step explanation:
hii... your answer is here. .......
let here theta= x.
so.....
cos x= 7/8.
so ....
sin x= √(1-cos^2x)
= √(1-(7/8)^2)
=√(1-49/64)
=√(15/64)
=(√15)/4.
now calculate ... (1+ sin x)/cos x=(1+√15/4)/7/8
=(4+√15)/4×8/7
=(8+2√15)/7.
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