cos theta cos(90-theta) / tan(90-theta) +cos theta sin(90-theta)
Answers
Answered by
1
Answer:
Given,
cos∅.cos(90°-∅)/(tan(90°-∅)) + cos∅.sin(90°-∅)
=> cos∅.sin∅/cot∅ + cos∅.cos∅
=> cos∅.sin∅/(cos∅/sin∅) + cos²∅
=> sin²∅+ cos²∅
= 1 Ans.
Similar questions