Question

cos theta × cos(90- theta)/ tan(90 - theta) + cos theta × sin(90-theta)

Answer 1

$= > \cos( \theta) \times \frac{ \cos(90 - \theta) }{tan(90 - \theta)} + \cos( \theta) \times \sin(90 - \theta) \\ = > \cos( \theta) \times \sin( \theta) \times \frac{1}{ \cot( \theta) } + \cos^{2} ( \theta) \\ = > \cos( \theta) \times \sin( \theta) \times \frac{ \sin( \theta) }{ \cos( \theta) } + \cos^{2}( \theta) \\ = > { \sin^{2} ( \theta) } + \cos^{2}( \theta) \\ = > 1$
Hope this helps.....