If a,b,c be the p th, q th and r th terms of an AP, prove that
a(q-r)+b(r-p)+c(p-q)=0.
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a=p (given)
b=q
c=r
p(q-r) +q(r-p) +r(p-q)
pq-pr+qr-pq+pr-qr
by solving the answer is 0
b=q
c=r
p(q-r) +q(r-p) +r(p-q)
pq-pr+qr-pq+pr-qr
by solving the answer is 0
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