cos tita ÷ 1- tan tita + sin tita ÷1-cos tita
Answers
Step-by-step explanation:
Let theta = x
tan x=3/4. , sin x=? and. sec x=?
sec^2x=1+tan^2x=1+9/16= 25/16
sec x=+/-(5/4). Answer
cos x= +/- 4/5
sin x=+/-√(1-cos^2x) = +/- √(1–16/25)=+/- √(9/25) = +/-3/5. Answer.
Second-method:-
tan x= 3/4
or. sin x/cos x= 3/4
or. (sin x)/3= (cos x)/4 =k(led)
or. sin x= 3k. , cos x=4k
sin^2x+cos^2x=1. =>. 9k^2+16k^2=1. or. 25k^2 = 1
k = +/-1/5
sin x= 3k = +/-3/5. Answer
and. cos x=4k = +/-(4/5). or sec x= +/-(5/4). Answer.
Go for the basics…
tan = opposite / adjacent
if opposite = 3x and adjacent = 4x, then based on Pythagoras theorem, hypotenuse = sqrt((3x)^2 + (4x)^2) = sqrt(9x^2 + 16x^2) = sqrt(25x^2) = 5x
Hence, sin theta = opposite / hypotenuse = 3x / 5x = 3/5
similarly, sec theta = hypotenuse/ adjacent = 5x / 4x = 5/4
You may also find all other trigonometric ratios now. No need to mug up formulae…
Answer:
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