Question

cos tita ÷ 1- tan tita + sin tita ÷1-cos tita​

Answer 1

Step-by-step explanation:

Let theta = x

tan x=3/4. , sin x=? and. sec x=?

sec^2x=1+tan^2x=1+9/16= 25/16

sec x=+/-(5/4). Answer

cos x= +/- 4/5

sin x=+/-√(1-cos^2x) = +/- √(1–16/25)=+/- √(9/25) = +/-3/5. Answer.

Second-method:-

tan x= 3/4

or. sin x/cos x= 3/4

or. (sin x)/3= (cos x)/4 =k(led)

or. sin x= 3k. , cos x=4k

sin^2x+cos^2x=1. =>. 9k^2+16k^2=1. or. 25k^2 = 1

k = +/-1/5

sin x= 3k = +/-3/5. Answer

and. cos x=4k = +/-(4/5). or sec x= +/-(5/4). Answer.

Go for the basics…

tan = opposite / adjacent

if opposite = 3x and adjacent = 4x, then based on Pythagoras theorem, hypotenuse = sqrt((3x)^2 + (4x)^2) = sqrt(9x^2 + 16x^2) = sqrt(25x^2) = 5x

Hence, sin theta = opposite / hypotenuse = 3x / 5x = 3/5

similarly, sec theta = hypotenuse/ adjacent = 5x / 4x = 5/4

You may also find all other trigonometric ratios now. No need to mug up formulae…

Answer 2

Answer:

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