cos x.cos 2x.cos 3x प्रदत्त फलनों का x के सापेक्ष अवकलन कीजिए
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dy/dx = - ( SinxCos2xCos3x + Sin2xCosxCos3x + 3Sin3xCosxCos2x) यदि y = Cosx. Cos2x . Cos3x
Step-by-step explanation:
dy/dx ज्ञात कीजिए
y = Cosx. Cos2x . Cos3x
dy/dx = -Sinx (Cos2x . Cos3x) - 2Sin2x(CosxCos3x) - 3Sin3x(Cosx. Cos2x)
=> dy/dx = - ( SinxCos2xCos3x + 2Sin2xCosxCos3x + 3Sin3xCosxCos2x)
एक और तरीका
y = Cosx. Cos2x . Cos3x
log y = log (Cosx. Cos2x . Cos3x)
=> log y = log (cosx) + log ( Cos2x) + log(Cos3x)
=> (1/y )dy/dx = -Sinx/Cosx - 2Sin2x/Cos2x - 3Sin3x/Cos3x
=> dy/dx = - y ( Tanx + 2Tan2x + 3Tan3x)
=> dy/dx = - Cosx. Cos2x . Cos3x ( Tanx + 2Tan2x + 3Tan3x)
=> dy/dx = - (SinxCos2xCos3x + 2Sin2xCosxCos3x + 3Sin3xCosxCos2x)
और अधिक जानें :
sin(x²+5)"
brainly.in/question/15286193
sin (ax+b) फलन का अवकलन कीजिए
brainly.in/question/15286166
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