(cos x+ cosy) ^2 + (sin x - sin y)^2= 4 sin^2 (x-y) /2
Answers
Answered by
1
Answer:
LHS :
(cosx+cosy)
2
+(sinx−siny)
2
=(cos
2
x+cos
2
y+2cosxcosy)+(sin
2
x+sin
2
y−2sinxsiny)
=(cos
2
x+sin
2
y)+(cos
2
x+sin
2
y)+2(cosxcosy−sinxsiny)
=1+1+2cos(x+y)
=2+2cos(x+y)
=2[1+cos(x+y)]
=4 cos
2
(
2
x+y
) = RHS
Answered by
11
Answer:
LHS:
(cosx+cosy)
2
+(sinx-siny)
2
=(cos
2
x+cos
2
y+2cosxcosy)+(sin
2
x+sin
2
y-2sinxsiny)
=(cos
2
x+sin
2
y)+(cos
2
x+sin
2
y)+2(cosxcosy-sinxsiny)
=1+1+2 cos(x+y)
=2+2 cos(x+y)
=2[1+cos(x+y)]
=4 cos
2
2
x+y
) = RHS
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