Question

Cos x=tan y, cot y=tan z,cot z=tan x then sin x=?

Answer 1

Answer:(tany)^2 or (cosx)^2

Step-by-step explanation:

Cotz=tanx

=Sinx/cosx

Sinx=cotz cosx

=( 1/tanz)×tany

=(1/coty)tany

=Tany tany

Sinx =( tany)^2

Sinx=( cosx)^2

Answer 2

so sin x=root 5-1 ÷2

Here is the solution