Question

cos150×tan300÷cos225+sin-30​

Answer 1

Answer:

Suppose we wish to find the exact°and sin 150°. (cos 150°, sin 150°) as shown. POQ we can see that OQ = cos 30° and PQ = sin 30°, so the coordinates of P are −cos 30°, sin 30°). and sin 150° = sin 30° = .