cos²θ(1 + tan²θ) = 1, Prove it
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Answered by
5
According to identity 1+tan^2theta=sec^2theta
So now we have cos^2theta×sec^2theta
We know we can write cos^2theta to 1/sec^2 theta
So it will be cancelled and answer will be 1
So now we have cos^2theta×sec^2theta
We know we can write cos^2theta to 1/sec^2 theta
So it will be cancelled and answer will be 1
Answered by
4
Step-by-step explanation:
As per the question,
We have been prove that cos²θ(1 + tan²θ) = 1
Consider LHS, we have
cos²θ(1 + tan²θ)
Now,
By using the trigonometric identity
sin²θ + cos²θ = 1
tanθ = sinθ/cosθ
We can write by putting the value of tanθ.
∴ cos²θ(1 + tan²θ)
cos²θ(1 + (sinθ/cosθ)²)
= sin²θ + cos²θ
= 1
= RHS
Therefore,
LHS = RHS
Hence, proved.
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