Question

sin²θ/cosθ+cosθ=secθ, Prove it

Answer 1

In the attachment I have answered this problem.

The following result has been applied
in proving this problem.

Sin^2(A) + Cos^2(A) =1

See the attachment for detailed solution.

Answer 2

QUESTION :
Sin²θ/cosθ+cosθ=secθ, Prove it

SOLUTION :
Given :
Sin²θ/cosθ+cosθ=secθ
L.H.S
(Sin²θ/cosθ)+cosθ
=( sin²θ + cos²θ)/cosθ
= 1 /cosθ
[By using trignometry identity ,sin²θ + cos²θ = 1]
= secθ [1 /cosθ = sec θ]

L.H.S = R.H.S

Hence, proved...

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