Question

cos2(45°+q)+cos2(45°-q)/tan(60°+q)* tan(30°-q)=1

Answer 1

Show that cos 2 (45 + theta) + cos 2 (45 - theta) / tan (60 + ... + sin^2(45 + theta) / tan(60 + theta) cot(60 + theta) = 1 / 1

Answer 2

haloo dear ... cos2(45 dg)+cos2(45dg-q)/tan(60dg)*tan(30dg-q)=1
ans is1/1