cos2 theta /1-sin2 theta =???
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Answer:
Step-by-step explanation:
taking R.H.S
tan(45-theta)
tan45-tantheta/1+tan45.tanx
1-tan theta/1+tan theta
byLHS
(1-tan²theta/1+tan²theta)/1+(2 tan theta)/1+tan²theta
(1-tan²theta/1+tan²theta)/(1+tan²theta+2 tan theta)(1+tan²theta)
then,it comes
(1-tan²theta)/(1+tan theta)²
(1-tan theta)(1+tan theta)/(1+tan theta)*(1+tan theta)
so
(1-tan theta)/(1+tan theta)
L.H.S=R.H.S
HENCE PROVED
yash2235:
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