cos24°+cos55°+cos125°+cos204°=
Answers
Answered by
8
⇒cos 24° +cos 55° +cos (180°-55°) +cos(180°+24°)
=cos 24° +cos 55° - cos 55° -cos 24°
=0
Answered by
1
I think the correct question is this:
The value of following is cos24° + cos55° + cos 125° + cos 204° + cos300°
A) -1/2
B) 1/2
C) 2
D) 1
Answer:
The value of
cos24∘+cos55∘+cos125∘+cos204∘+cos300∘
We know that, cos(180∘±θ)
=−cosθ
⇒cos24∘+cos55∘+cos(18∘−55∘)
+cos(180∘+24∘)+cos(360∘−60∘)
⇒cos24∘+cos55∘−cos55∘−cos24∘+cos60∘
=cos60∘
=12
If there is any confusion please leave a comment below.
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