Math, asked by Knightwar, 1 year ago

cos2A-cos2B-cos2C=-1+4cosAcosBcosC

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Answered by laksssss
6
Cos2A-Cos2B-Cos2C

=-2Sin(A+B)Sin(A-B)-1+2Sin²C

A+B+C=π
A+B=π-C

=-2Sin(π-C)Sin(A-B)-Cos2C

=-2SinCSin(A-B)-1+2Sin²C

=-2SinC[Sin(A-B)-SinC]-1

=-2SinC[Sin(A-B)-Sin(π-(A+B)]-1

=-2SinC[Sin(A-B)-Sin(A+B)]-1

=-2SinC[-2CosASinB]-1

=-4CosASinBSinC-1

=-1-4CosASinBSinC

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