Math, asked by yashikachainani76, 1 year ago

cos2a cos3a - cos 2A cos 7 a + cos a cos 10 a divide by sin 4A sin 3A - sin 2A sin 5A + sin 4Asin7A = cot6Acot5A

Answers

Answered by mathdude200

21

in second last step
use
cos C + cos D

cos C - cos D

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