Math, asked by Destroyer48, 1 year ago

cos²A +tan²A -1÷sin²A

Answers

Answered by tamanna35
0
(cos^2A - 1) +tan^2A ÷sin^2A ;; or sin^2A+tan^2A÷ sin^2A ;; or sin^2A +sin^2A/ cos^2A ÷sin^2A ;; or sin^2A cos^2A+sin^2A / cos^2A÷sin^2A or sin^2A (cos^2A + 1) / cos^2A÷sin^2A ;; or cos^2A+1 ÷cos^2A :: or 1+1/cos^2A Or 1 + sec^2A

Destroyer48: i think its wrong
Destroyer48: because cos^2A-1 is not sin^2A
tamanna35: sin^2A +cos^2A=1 using this identity it is same
tamanna35: tell if it helps you
Destroyer48: i got it but using different method
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