cos2xsin4x integrate it
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Answered by
1
Solution is in the attached pic :)
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keerthi1208:
i have used another formula
which one ?
what's your answer .. send me your answer I'll check if it's correct or not !
sinAcosB=1/2sin(A+B)+sin(A-B)
by using the above mentioned formula,i am getting the book back answer
yes .. that's right
you can do by that also
it's obviously right
:)
ok
Answered by
2
∫cos2xsin4xdx
∫cos2x.2sin2xcos2xdx
2∫sin2xcos²2xdx (equation 1)
Take cos2x=t
⇒-2sin2xdx=dt
⇒dx=-dt/2sin2x
substituting dx in equation 1
⇒-∫t²dt
-t³/3+c
⇒-cos³2x/3+c
∫cos2x.2sin2xcos2xdx
2∫sin2xcos²2xdx (equation 1)
Take cos2x=t
⇒-2sin2xdx=dt
⇒dx=-dt/2sin2x
substituting dx in equation 1
⇒-∫t²dt
-t³/3+c
⇒-cos³2x/3+c
hii
thanks
but this one is not correct
Simplify the ans given in the book you may get the same answer as above....
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