The sum of 3 consecutive integer is 51 the middle one is
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n+n+1+n+2=51
3n=48
n=12
middle one is n+1=13
3n=48
n=12
middle one is n+1=13
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Let three consecutive no.s be n , ( n +1) & (n+2 )
A.T.Q ,
n+n+1+n+2=51
3n=48
n=12
middle one is n+1=13
A.T.Q ,
n+n+1+n+2=51
3n=48
n=12
middle one is n+1=13
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