Math, asked by lakshmisujatha, 8 months ago

cos3tita = cos²tita then the general solution is

Answers

Answered by anushka33244

0

HEY MATE....

here is ur ans...

3θ=2nπ±2θ[⋅.⋅n∈1]

3θ=2nπ+2θ

3θ−2θ=2nπ

θ=2nπ

or3θ+2θ=2nπ

5θ=2nπ

θ=

5

2

nπ

HOPE MY EFFORTS SATISFIED UH....

HOPE IT HELPS❤

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