Question

two boys each weighing 50 kg are sitting on a bench close to each other separated by 0.5m
what is the magnitude of gravitational force between them ?

Answer 1

Answer:

6.67*10^-7N

Explanation:

see the pic thank you

Answer 2

Answer:

The magnitude of the gravitational force between them is 6.67×10⁻⁷N.

Explanation:

The gravitational force is given as,

$F=\frac{GM_1M_2}{d^2}$           (1)

Where,

F=gravitational force acting between the bodies

M₁&M₂=mass of the respective bodies

d=separation between the bodies

G=universal gravitational constant=6.67×10⁻¹¹N kg⁻²m²

From the question we have,

M₁=M₂=50Kg

d=0.5m

By substituting the values in equation (1) we get;

$F=\frac{6.67\times 10^-^1^1\times 50\times 50}{(0.5)^2}$

$F=6.67\times 10^-^7N$

Hence, the magnitude of the gravitational force between them is 6.67×10⁻⁷N.