[(cos3x+2cos5x+cos7x)÷(cosx +2cos3x+cos5x)]=cos2x-sin2x×tan3x
Answers
Answered by
6
(cos7x+cos3x)+2cos5x/(cos5x+cosx)+2cos3x. ........2cos5xcosx+2cos5x/2cos3xcos2x+2cos3x.......2cos5x (cos2x+1)/2cos3x (cos2x+1)....cos5x/cos3x.....cos (3x+2x)/cos3x......cos3xcos2x-sin3xsin2x/cos3x.. cos3xcos2x/cos3x-sin3xsin2x/cos3x.... cos3x-sin3xsin2x. .....solved
Hope this helpes you :)
Similar questions