Math, asked by kpulkit15234, 11 months ago

cos4a+cos3a+cos2a/sin4a+sin3a+sin2a=cot3a

Answers

Answered by sandy1816

4

Step-by-step explanation:

=(cos4A+cos2A)+cos3A/(sin4A+sin2A)+sin3A

={(2cos6A/2cos2A/2)+cos3A}/{(2sin6A/2cos2A/2)+sin3A}

={2cos3AcosA+cos3A}/{2sin3AcosA+sin3A}

=cos3A(2cosA+1)/sin3A(2cosA+1)

=cos3A/sin3A

=cot3A

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