Math, asked by akankhyabiswal62, 7 months ago

cos4x cos5x sin2x dx

Answers

Answered by srustimishrais
0

Step-by-step explanation:

hope this helps you!

you need to take common the cos first and then take dt

Attachments:
Answered by amitsnh
0

Answer:

cos4x cos5x sin2x dx

(1/2)*2cos4x cos5x sin2x dx

(1/2)* (cos9x + cosx)sin2x dx

(1/2)*[cos9xsin2x dx + sin2x cosx dx]

(1/4)*[2cos9x sin2x dx + 2 sin2x cosx dx]

(1/4)*[sin11x dx - sin7x dx + sin3x dx + sinx dx]

= (1/4)*[ -cos11x/11 + cos7x/7 - cos3x/3 - cosx] + c

= (1/924)[33cos7x - 21 cos11x - 77 cos3x - 231 cosx] + c

Similar questions