cos4x cos5x sin2x dx
Answers
Answered by
0
Step-by-step explanation:
hope this helps you!
you need to take common the cos first and then take dt
Attachments:
Answered by
0
Answer:
cos4x cos5x sin2x dx
(1/2)*2cos4x cos5x sin2x dx
(1/2)* (cos9x + cosx)sin2x dx
(1/2)*[cos9xsin2x dx + sin2x cosx dx]
(1/4)*[2cos9x sin2x dx + 2 sin2x cosx dx]
(1/4)*[sin11x dx - sin7x dx + sin3x dx + sinx dx]
= (1/4)*[ -cos11x/11 + cos7x/7 - cos3x/3 - cosx] + c
= (1/924)[33cos7x - 21 cos11x - 77 cos3x - 231 cosx] + c
Similar questions